RegEx

Find every run of digits in the text.

import re

text = "call 0176 1234567"
# print the list of digit runs

\\d+ matches one or more digits. Use a raw string.

import re

text = "call 0176 1234567"
print(re.findall(r"\d+", text))

search returns None here. Print 'nothing matched' rather than crashing.

import re

found = re.search(r"\d+", "no digits here")
print(found.group())

Check the result before calling .group().

import re

found = re.search(r"\d+", "no digits here")
if found:
    print(found.group())
else:
    print("nothing matched")

The greedy pattern swallows the whole string. Make it match each tag separately.

import re

html = "<b>bold</b>"
print(re.findall(r"<.+>", html))

A ? after the + makes it lazy.

import re

html = "<b>bold</b>"
print(re.findall(r"<.+?>", html))